Проблема работы в менеджер меню Joomla 2.5 - Joomla 2.5: Общие вопросы

Joomla! 500 - Обнаружена ошибка. Unknown column 'a.ordering' in 'field list' SQL=SELECT a.id, a.menutype, a.title, a.alias, a.note, a.path, a.link, a.type, a.parent_id, a.level, a.published as apublished, a.component_id, a.ordering, a.checked_out, a.checked_out_time, a.browserNav, a.access, a.img, a.template_style_id, a.params, a.lft, a.rgt, a.home, a.language, a.client_id,CASE a.type WHEN 'component' THEN a.published+2*(e.enabled-1) WHEN 'url' THEN a.published+2 WHEN 'alias' THEN a.published+4 WHEN 'separator' THEN a.published+6 END AS published,l.title AS language_title, l.image as image,u.name AS editor,c.element AS componentname,ag.title AS access_level,e.name AS name FROM `gok_menu` AS a LEFT JOIN `gok_languages` AS l ON l.lang_code = a.language LEFT JOIN `gok_users` AS u ON u.id = a.checked_out LEFT JOIN `gok_extensions` AS c ON c.extension_id = a.component_id LEFT JOIN gok_viewlevels AS ag ON ag.id = a.access LEFT JOIN gok_extensions AS e ON e.extension_id = a.component_id WHERE a.id > 1 AND a.client_id = 0 AND (a.published IN (0, 1)) AND a.menutype = 'mainmenu' ORDER BY a.lft asc Unknown column 'a.ordering' in 'field list' SQL=SELECT a.id, a.menutype, a.title, a.alias, a.note, a.path, a.link, a.type, a.parent_id, a.level, a.published as apublished, a.component_id, a.ordering, a.checked_out, a.checked_out_time, a.browserNav, a.access, a.img, a.template_style_id, a.params, a.lft, a.rgt, a.home, a.language, a.client_id,CASE a.type WHEN 'component' THEN a.published+2*(e.enabled-1) WHEN 'url' THEN a.published+2 WHEN 'alias' THEN a.published+4 WHEN 'separator' THEN a.published+6 END AS published,l.title AS language_title, l.image as image,u.name AS editor,c.element AS componentname,ag.title AS access_level,e.name AS name FROM `gok_menu` AS a LEFT JOIN `gok_languages` AS l ON l.lang_code = a.language LEFT JOIN `gok_users` AS u ON u.id = a.checked_out LEFT JOIN `gok_extensions` AS c ON c.extension_id = a.component_id LEFT JOIN gok_viewlevels AS ag ON ag.id = a.access LEFT JOIN gok_extensions AS e ON e.extension_id = a.component_id WHERE a.id > 1 AND a.client_id = 0 AND (a.published IN (0, 1)) AND a.menutype = 'mainmenu' ORDER BY a.lft asc LIMIT 0, 100 Unknown column 'a.ordering' in 'field list' SQL=SELECT a.id, a.menutype, a.title, a.alias, a.note, a.path, a.link, a.type, a.parent_id, a.level, a.published as apublished, a.component_id, a.ordering, a.checked_out, a.checked_out_time, a.browserNav, a.access, a.img, a.template_style_id, a.params, a.lft, a.rgt, a.home, a.language, a.client_id,CASE a.type WHEN 'component' THEN a.published+2*(e.enabled-1) WHEN 'url' THEN a.published+2 WHEN 'alias' THEN a.published+4 WHEN 'separator' THEN a.published+6 END AS published,l.title AS language_title, l.image as image,u.name AS editor,c.element AS componentname,ag.title AS access_level,e.name AS name FROM `gok_menu` AS a LEFT JOIN `gok_languages` AS l ON l.lang_code = a.language LEFT JOIN `gok_users` AS u ON u.id = a.checked_out LEFT JOIN `gok_extensions` AS c ON c.extension_id = a.component_id LEFT JOIN gok_viewlevels AS ag ON ag.id = a.access LEFT JOIN gok_extensions AS e ON e.extension_id = a.component_id WHERE a.id > 1 AND a.client_id = 0 AND (a.published IN (0, 1)) AND a.menutype = 'mainmenu' ORDER BY a.lft asc

Ваш сервер соответствует минимальным техническим требованиям к Joomla 2.5? Если да, то пробуйте отключать установленные расширения.

Отсутствует поле ordering в таблице gok_menu. Открываем таблицу смотрим куда делось.

Создал в ручную поле не чего не изменилось