"You have an error in your SQL syntax" - Почему? - Joomla 1.5: Общие вопросы

defined( '_JEXEC' ) or die( 'Restricted access' );

$db =& JFactory::getDBO();
$user =& JFactory::getUser();

$usname = $user->username;
$id = $user->id;

$params = new JParameter($user->params);
$value = $params->get('someParam');
if($value==''){
	$db->setQuery("INSERT INTO #__users (params) VALUES('lastLevels=0\r\n') WHERE id = '$id' ");
	$db->query();
	echo $db->stderr();
}

INSERT INTO #__users params VALUES('lastLevels=0\r\n') WHERE id = '$id'

$db->setQuery("UPDATE #__users SET params = 'lastLevels=0\r\n' WHERE id = '$id' ");

$db->setQuery("UPDATE #__users SET params = 'lastLevels=0\r\n' WHERE params <> '' AND  id = '$id' ");

$db->setQuery("UPDATE #__users SET params = params+'lastLevels=0\r\n' WHERE params <> '' AND  id = '$id' ");

$query = 'INSERT INTO #__users (params) VALUES ("lastLevels=0\r\n") WHERE id =' . (int) $id;
$db->setQuery($query);

$db->setQuery("UPDATE #__users SET params = params+'lastLevels=0\r\n' WHERE params <> '' AND  id = '$id' ");

$db->setQuery("UPDATE #__users SET params = 'какая-то тупая строка просто для примера'  WHERE id = '$id' ");