Получить данные из поля " file", и передать в файл обработчик - Разработка расширений для Joomla

<field name="file" type="file"  accept="csv" id="file"  />

<form class="form-horizontal well" action="../import.php" method="post" name="upload_excel" enctype="multipart/form-data">
<input type="file" name="file" id="file" class="input-large">
<button type="submit" id="submit" name="Import" class="btn btn-primary button-loading" data-loading-text="Loading...">Upload</button>
</form>

action="import.php"

<form action="../import.php" >
<input type="file" name="file">
<button type="submit" >Upload</button>
</form>

<field name="file" type="file"  accept="csv" id="file"  />

if (isset($_POST["Import"])) {
echo $filename = $_FILES["file"]["tmp_name"];
if ($_FILES["file"]["size"] > 0) {
$file = fopen($filename, "r");
while (($emapData = fgetcsv($file, 10000, ","))!== FALSE) {}

<input type="file" name="jform[params][file]" id="jform_params_file"/>

helper.php

mod_name.php