Как сформировать код PHP для нескольких комбинаций параметров? - Расширения форумчан

				if (($this->params->def('param1', '1'))&&($this->params->def('param2', '1'))&&($this->params->def('param3', '1'))) {

					$document->addScript(JURI::base($pathonly = true). '/media/plg_blablabla/js/blablabla.js');

				}

$cond = $this->params->get('param1', '1'). $this->params->get('param2', '1'). $this->params->get('param3', '1');
if ($cond == '000') {
} else if ($cond == '001') {
...
}

$func = 'func'.$cond;
$this->$func()

$params = json_decode($this->params,1);
$scripts = [
        000=>'script1.js',
        100=>'script2.js',
        110=>'script3.js',
        011=>'script4.js',
        001=>'script5.js',
        101=>'script6.js',
        //......
    ];
$combs = (int)$params['param1'].(int)$params['param2'].(int)$params['param3'];
$scriptByCombination = $scripts[$combs];

$cond = $this->params->get('param1',0). $this->params->get('param2',0). $this->params->get('param3', 0);

$file = 'script_'.$param1.'-'.$param2.'-'.$param3.'.js';
$document->addScript(JURI::base($pathonly = true). '/media/plg_blablabla/js/'.$file);