Как создать повторяющееся поле внутри повторяющейся subform ? - Joomla 3.x: Общие вопросы

<?xml version="1.0" encoding="UTF-8"?>
<form>
    <field name="question" type="textarea" label="Question" cols="40" rows="8"/>
	<fieldset name="answers">
		<field name="answer" type="text" label="answer" multiple="true" />
	</fieldset>
</form>

	<config>
		<fields name="params">
			<fieldset name="basic" addfieldpath="/plugins/jshoppingproducts/dopfields/fields">
				<field name="fields" type="subform" formsource="plugins/jshoppingproducts/dopfields/table.xml" min="1" max="30" multiple="true" layout="joomla.form.field.subform.repeatable-table" groupByFieldset="true" label="Subform Field" description="Subform Field Description" />
			</fieldset>
		</fields>
	</config>

<?xml version="1.0" encoding="UTF-8"?>
<form>
	<fieldset name="list_templates_modal" label="Блоки">
		<field name="number" label="Номер*" type="text" filter="int" />
		<field name="name" label="Название вкладки" type="text" />
	</fieldset>
</form>

<field name="fileJsRules" type="subform" multiple="true"
					   formsource="plugins/system/[<!-- PLUGIN NAME -->]/exampleform.xml"
					   label="Subform Field" description="Subform Field Description" />

<?xml version="1.0" encoding="UTF-8"?>
<form>
    <fieldset name="section1" label="Section1">
        <field name="example_text" type="text" label="Example Text"/>
        <field name="example_textarea" type="textarea" label="Example Textarea" cols="40" rows="8"/>
    </fieldset>
    <fieldset name="section2" label="Section2">
        <field name="example_list"
               type="list"
               multiple="true"
               default=""
               class="advancedSelect"
               label="Example List">
            <option value="One">One</option>
            <option value="Two">Two</option>
            <option value="three">three</option>
            <option value="four">four</option>
            <option value="five">five</option>
        </field>
    </fieldset>
</form>

document.addEventListener("DOMContentLoaded", function () {   
     jQuery(document).on('subform-row-add', function(event, row){
        jQuery(row).find('select').chosen();
    })
});